Warrensville Heights, Ohio

Warrensville Heights, Ohio
Motto: 
"The Friendly City"
Location in Cuyahoga County and the state of Ohio
Location in Cuyahoga County and the state of Ohio
Coordinates: 41°26′19″N 81°31′24″W / 41.43861°N 81.52333°W / 41.43861; -81.52333
CountryUnited States
StateOhio
CountyCuyahoga
Village incorporated1927 [1]
Incorporated1960 [1]
Government
 • TypeMayor-council
Area
 • Total4.13 sq mi (10.69 km2)
 • Land4.12 sq mi (10.68 km2)
 • Water0.01 sq mi (0.01 km2)  0.24%
Elevation1,037 ft (316 m)
Population
 • Total13,789
 • Density3,344.41/sq mi (1,291.27/km2)
Time zoneUTC-5 (EST)
 • Summer (DST)UTC-4 (EDT)
Zip code
44122, 44128
Area code216
FIPS code39-80990[5]
GNIS feature ID1047579[3]
Websitewww.cityofwarrensville.com

Warrensville Heights is a city located in Cuyahoga County, Ohio, United States. It is an East Side suburb of Cleveland. The population was 13,789 at the 2020 U.S. Census.[4]

References